- 70 名前：１３２人目の素数さん mailto:sage [2007/06/09(土) 14:26:36 ]
- >15
[M.1769]
Determine a formula for the coefficient of x^i･y^j in
P_n(x,y) = Σ[k=0,n] C[2n+1,2k+1] x^(n-k)･(x+y)^k.
(略解)
{(1+u)^(2n+1) - (1-u)^(2n+1)}/(2u) = Σ[k=0,n] C[2n+1,2k+1] (u^2)^k = Q(u^2)
とおくと,
P_n(x,y) = (x^n)Q({x+y}/x) = Σ[i=0,n] C[n+i,n-i] (4x)^i･y^(n-i) = Σ[j=0,n] C[2n-j,j] (4x)^(n-j)･(y^j).
ﾃﾍｯ
