- 212 名前：１３２人目の素数さん [2024/03/11(月) 03:33:28.30 ID:iZ0/EVy6.net]
- >>175
1 - 1/z = e^{(5π/6)ｉ},
1/z = 1 - e^{(5π/6)ｉ} = (2+√3 -ｉ)/2,
1/|z|^2 = (1/z)(1/z*) = 2{1 - cos(5π/6)}
= 2{1 + cos(π/6)} = 2 + √3,
|z|^2 = 2 - √3,
z = |z|^2 (1/z~)
= (2-√3) (2+√3 +ｉ)/2
= 1/2 + (2-√3)/2・ｉ,
より
a = 1/2, b = (2-√3)/2,
