時枝記事の類似は、2013年12月09日にmathoverflowで、議論されている 二人の数学Dr Alexander Pruss 氏と Tony Huynh氏と、それ以外に質問者Denis氏(彼はコンピュータサインスの人)の周囲の人("other people argue it's not ok") たちは、「時枝の議論は測度論的に不成立」と言っている
(参考) https://mathoverflow.net/questions/151286/probabilities-in-a-riddle-involving-axiom-of-choice Probabilities in a riddle involving axiom of choice Denis氏 Dec 9 '13 (抜粋) ・・・but other people argue it's not ok, because we would need to define a measure on sequences, and moreover axiom of choice messes everything up.
answered Dec 11 '13 at 21:07 Math Dr. Alexander Pruss 氏 ・・・But we have no reason to think the event of guessing correctly is measurable with respect to the probability measure induced by the random choice of sequence and index i ・・・Intuitively this seems a really dumb strategy.
answered Dec 9 '13 at 17:37 Math Dr. Tony Huynh氏 ・・・If it were somehow possible to put a 'uniform' measure on the space of all outcomes, then indeed one could guess correctly with arbitrarily high precision, but such a measure doesn't exist.