- 514 名前：デフォルトの名無しさん [2005/07/05(火) 17:23:06 ]
- 長くなってすみません。
Schemeの手続きとそのスコープについて教えてください。
たとえば
[ソースコード]------------------------------------------------------------
.1: (define a_proc
.2: (lambda (n k)
.3: (if (null? n)
.4: ; true-clause
.5: (begin
.6: (newline)
.7: (write 'true-clause) (newline)
.8: (write 'n=) (write n) (newline)
.9: (write 'k=) (write k) (newline)
10: (k '()))
11: ; false-clause
12: (begin
13: (newline)
14: (write 'false-clause) (newline)
15: (write 'n=) (write n) (newline)
16: (write 'k=) (write k) (newline)
17: (a_proc (cdr n)
18: (lambda (u)
19: (write 'n=) (write n) (newline)
20: (write 'k=) (write k) (newline)
21: (write 'u=) (write u) (newline)
22: (k (append n u))))))))
23: (a_proc '(a) (lambda (x) x))
というコードを処理系に読ませると、
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