- 309 名前：296 [2008/02/11(月) 12:29:49 ]
- こんな感じかな
for (int i = 0; i < 10; i++) {
if (x[i] == 0) {
goto A_FAILED;
} else {
a /= x[i];
}
for (int i = 0; i < 10; i++) {
if (y[i] == 0) {
goto B_FAILED;
} else {
b /= y[i];
}
return 0;
B_FAILED:
something
A_FAILED:
something
return -1;
