- 371 名前：Kummer ◆g2BU0D6YN2 [2007/05/20(日) 11:16:11 ]
- >>367 より
θ_n = (-b_n + √D)/2|a_n| とおくと、
φ_FQ(f_n) = (θ_n, sign(a_n)) = (1/(1/θ_n), sign(a_n))
よって
φ_FQ( (3, 2, -4) ) = ( (-2 + √D)/6, 1 ) = (1/((2 + √D)/8), 1)
φ_FQ( (-4, 6, 1) ) = ( (-6 + √D)/8, 1 ) = (1/((6 + √D)/2), -1)
φ_FQ( (1, 6, -4) ) = ( (-6 + √D)/2, 1 ) = (1/((6 + √D)/8), 1)
φ_FQ( (-4, 2, 3) ) = ( (-2 + √D)/8, 1 ) = (1/((2 + √D)/6), -1)
φ_FQ( (3, 4, -3) ) = ( (-4 + √D)/6, 1 ) = (1/((4 + √D)/6), 1)
φ_FQ( (-3, 2, 4) ) = ( (-2 + √D)/6, 1 ) = (1/((2 + √D)/8), -1)
φ_FQ( (4, 6, -1) ) = ( (-6 + √D)/8, 1 ) = (1/((6 + √D)/2), 1)
φ_FQ( (-1, 6, 4) ) = ( (-6 + √D)/2, 1 ) = (1/((6 + √D)/8), -1)
φ_FQ( (4, 2, -3) ) = ( (-2 + √D)/8, 1 ) = (1/((2 + √D)/6), 1)
φ_FQ( (-3, 4, 3) ) = ( (-4 + √D)/6, 1 ) = (1/((4 + √D)/6), -1)
φ_FQ( (3, 2, -4) ) = ( (-2 + √D)/6, 1 ) = (1/((2 + √D)/6), 1)
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