- 729 名前：１３２人目の素数さん mailto:sage [2021/07/09(金) 01:48:22.08 ID:JOXJl2Ba.net]
- >>694
(x-a/2)^3 + {t 't '+(aa-1)(aa+4b)/4}(x-a/2) - a(aa+4b)t '/2 = 0,
から
x = a/2 + { a(aa+4b)t '/4 + √[(a(aa+4b)t '/4)^2 + (1/27){t 't '+(aa-1)(aa+4b)/4}^3] }^(1/3)
+ { a(aa+4b)t '/4 - √[(a(aa+4b)t '/4)^2 + (1/27){t 't '+(aa-1)(aa+4b)/4}^3] }^(1/3)
ここに
t' = t - aa/2 - b,
