- 474 名前：１３２人目の素数さん mailto:sage [2020/09/06(日) 13:07:21.76 ID:HYDaJwjZ.net]
- >>453
m = floor(n/2) とおくと
{n-1, n} = {2m. 2(n-m)-1}
b[n] = a[2m] → α (n→∞)
c[n] = a[2(n-m)-1] → α (n→∞)
a[n] + a[n-1] = b[n] + c[n] → α+α (n→∞)
a[n] - a[n-1] = ±(b[n] - c[n]) = ±((b[n]-α) - (c[n]-α)) → 0 (n→∞)
辺々たす。
