（>>28より再録） https://mathoverflow.net/questions/151286/probabilities-in-a-riddle-involving-axiom-of-choice Probabilities in a riddle involving axiom of choice Denis氏 Dec 9 '13 (抜粋) answered Dec 11 '13 at 21:07 Math Dr. Alexander Pruss 氏 ”The probabilistic reasoning depends on a conglomerability assumption, namely that given a fixed sequence u^→ , the probability of guessing correctly is (n?1)/n, then for a randomly selected sequence, the probability of guessing correctly is (n?1)/n. But we have no reason to think the event of guessing correctly is measurable with respect to the probability measure induced by the random choice of sequence and index i, and we have no reason to think that the conglomerability assumption is appropriate.” と書いてある ”The probabilistic reasoning depends on a conglomerability assumption”つまり、確率的理由付けは、”conglomerability assumption”が成り立っている必要があるという
この”conglomerability”は、mathoverflow中にも説明がある。 また、本があるよ。下記の”Infinity, Causation, and Paradox Alexander R. Pruss”P75-77とかに詳しい説明がある （下記のGoogleのビューで、かなり読めるよ）
https://books.google.co.jp/books?id=RXBoDwAAQBAJ&printsec=frontcover&hl=ja#v=onepage&q&f=false https://books.google.co.jp/books?id=RXBoDwAAQBAJ&printsec=frontcover&hl=ja#v=onepage&q=conglomerability&f=false Infinity, Causation, and Paradox Alexander R. Pruss Oxford University Press, 2018/07/26 - 248 ページ
