f is not differentiable at all irrational numbers.
All sequences of irrational numbers (ai≠ x0)_(i=1〜∞ ) converging to the irrational point x0 imply a constant sequence (f(ai)=0)_(i=1〜∞ ), identical to 0,
and so lim _(i→ ∞ )| (f(ai)-f(x0))/(ai-x0))|=0.
According to Hurwitz's theorem, there also exists a sequence of rational numbers (bi=ki/i)_(i=1〜∞ ),
converging to x0, with (ki∈ Z ,i∈ N )) (ki∈ Z ,i∈ N )) coprime and |ki/i-x0|< 1/(√ 5)* i^2).
Thus for all i,: |(f(bi)-f(x0))/ (bi-x0)| > (1/i - 0)/(1/((√ 5)* i^2)))= √ 5* i ≠ 0 and so f is not differentiable at all irrational x0. (引用終り)