- 458 名前：１３２人目の素数さん [2016/08/16(火) 22:39:17.29 ID:BueGbAd9.net]
- f(x)(x^3-2)+g(x)(x^2+2x+2)
A := x^3 - 2
B := x^2 + 2*x +2
C := x + 1/2
とおく。
A = (x - 2)*B + (4*x + 2) = (x - 2)*B + 4*(x + 1/2) = (x - 2)*B + 4*C
B = (x + 3/2)*C + 29/16
29/16 = B - (x + 3/2)*C
4*C = A - (x - 2)*B
29/4 = 4*B - (x + 3/2)*4*C = 4*B - (x + 3/2)*{A - (x - 2)*B} = -(x + 3/2)*A + {4 + (x + 3/2)*(x - 2)}*B
29/2 = -(2*x + 3)*A + {8 + (2*x + 3)*(x - 2)}*B = -(2*x + 3)*A + (2*x^2 - x + 2)*B
1 = (-2/29)*(2*x + 3)*A + (2/29)*(2*x^2 - x + 2)*B
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